python统计字母、空格、数字等字符个数

# -*- coding: utf-8 -*-
# 要求：输入一行字符，分别统计出其中英文字母、空格、数字和其它字符的个数。
def count(s):
    count_a=count_z=count_o=count_s=0
    for i in s:
        if (ord(i)>=97 and ord(i)<=122) or (ord(i)>=65 and ord(i)<=90):
            count_a=count_a+1
        elif ord(i)>=48 and ord(i)<=57:
            count_z=count_z+1
        elif ord(i)==32:
            count_s=count_s+1
        else:
            count_o=count_o+1
    print "英文字母个数：%d个"%count_a
    print "数字个数：%d个"%count_z
    print "其他字符个数：%d个"%count_o
    print "空格个数：%d个"%count_s


if __name__=="__main__":
    s=raw_input("请输入一串字符：")
    count(s)

运行结果：

请输入一串字符：{“”O: UIK YTJ ET_+(_^@#%@#$^#%*&456587978957FHSJHSRHFDHDFaHSHYWER YWERF R454qggsdhshrths
英文字母个数：48个
数字个数：15个
其他字符个数：22个
空格个数：7个

总结：

ord()将字符转换为ASCII码